$\frac{\cot^2x}{cscx}=\frac{1-sin^2x}{sinx}$
$\left(5a-7b\right)\left(a+3b\right)$
$\cot^2x\sec^2x-1=1$
$\arctan\left(\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}\right)$
$-\left|\left(-32\right)+\left(-49\right)\right|$
$2^3\sqrt{4}-3$
$x^2+9x-15$
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