$\int2x\cdot\sqrt[3]{x+4}dx$
$27^{x^4}=9^{24}$
$\frac{\left(4x^2+2x+3x^3-3\right)}{\left(x+1\right)}$
$\frac{dy}{dx}=x\:^2\sqrt{y}$
$x^2+x-240$
$\lim_{x\to-1}\:x^2-5x-1$
$-7+2a>9$
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