$\left(3y^2+2\right)\left(3y^2-2\right)$
$x^2+4x-120=0$
$\left(x-2y\right)\left(a-2b\right)$
$52-13+143$
$\frac{dy}{dx}=\frac{\left(2xy\right)}{\left(x^2-2\right)\left(x^2+3\right)}$
$-60:-300$
$\frac{dy}{dx}=2\left(\sqrt{y+1}\right)\cos\left(x\right)$
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