$\int\frac{\sqrt{y^2+9}}{y}dy$
$\frac{dx}{dy}+\frac{4x}{y}=y^2-1$
$x^3\left(5-x\right)^3$
$7.25-\left(0.5\right)$
$\frac{\left(3m^{-1}n^{2}\right)^{4}}{\left(2m^{-2}n\right)^{3}}$
$0.31-0.12$
$x^2+xy+y=x-4$
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