$\int\left(3x+6\right)^2dx$
$\frac{dy}{dx}=\left(4+x\right)y=y^3$
$x^4+5x-6$
$\left(m^{-\frac{5}{2}}\right)^{-7}$
$3^2^{\left(\frac{5}{2}\right)-1}$
$4\left(3\right)\:.\:4\left(-7\right)$
$x^2=20x$
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