$f\left(x\right)=\left(x-7\right)^5$
$f\:\left(x\right)=\sqrt{x}^2\:-\:1$
$\lim_{x\to1}\sin\left(7x\right)+2x^2.\ln\left(x\right)$
$\frac{8x^5\:-\:19x^4\:+\:11x^2\:-\:11}{x\:-\:2}$
$\log_{11}\left(11\right)$
$69+2020$
$\left(\frac{2}{5}\right)^{12}.\left(\frac{3}{4}\right)^{14}$
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