$9+9\cos x=6\sin^2x$
$\int\frac{15}{4}x^{\frac{5}{2}}dx$
$\int_6^9\left(9x^2-4x+7\right)dx$
$\int\frac{2-x^3}{\left(x^4-x^3\right)}dx$
$-6-5x^2+7x^2-7y^3+y^3+2x^2$
$\left(10\right)+3\left(14\right)-12+\left(4\right)$
$4.9\infty-5$
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