$e^y\:y^'=\left(4x^2+2x-3\right)$
$xy'-2y=x^3e^x$
$\int\frac{3x^4+6x^2+x+3}{x^5+2x^3+x}dx$
$\left(6t^3-8r^2\right)^2$
$\:-78\:x\:22\:$
$( 4 x ^ { 4 } y ^ { 3 } - 5 x y ) ^ { 2 }$
$\sqrt[3]{\sqrt[2]{\sqrt{x}}}$
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