$\lim_{x\to-\infty}\left(\frac{\sqrt[2]{1+16x^6}}{3-x^3}\right)$
$16\cdot\sqrt{81}$
$\left(-2-3y\right)\cdot\left(6-y\right)$
$\int\left(\frac{3}{\left(x-2\right)^3\left(x+1\right)}\right)dx$
$\frac{x+4}{7}=-3$
$-108m^2n+144mn^227m^3-64n^3$
$x2-3x-55$
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