$\frac{a^2-6a}{a^3+3a^2}$
$\left(1+\sqrt{\infty\:+2}-\sqrt{\infty\:}\right)^{\sqrt{\infty}}$
$xy=\left(1+x^2\right)\frac{dy}{dx}$
$\frac{x^3+5x^2+10x-15}{x-4}$
$\frac{x^2-2x+4}{2-x}$
$\left(\frac{x}{2}+\frac{y^2}{3}\right)$
$2+8-1$
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