$\sqrt{12ab^4}\cdot\sqrt[3]{5a^2b^5}\cdot\sqrt[5]{\left(ab\right)^3}$
$\left(x^4-2y^2\right)^3$
$528^2-527^2$
$-25+x=41$
$x\cdot\tan\left(47\right)=\left(x+389\right)\tan\left(17\right)$
$\left(-7\right)\left(-4\right)-10$
$x\frac{dy}{dx}+y=cos\:x$
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