$\log e\left(40\right)=n$

$\frac{tan^2\left(x\right)}{sec\left(x\right)}=\frac{\left(sec^2\left(x\right)-1\right)}{sec\left(x\right)}$

$\int\frac{2x^{3}-5x^{2}+4x-4}{x^{2}-1}dx$

$\int x\left(2x^2-6x+\frac{3}{x^2+1}\right)dx$

$\frac{-18x}{6e^{3x}}$

$\left(-7\cdot5\right)^6$

$\left(a^2+b\right)\left(a^4-a^2b+b^2\right)$