$\log\left(4X^2\right)=128$
$\log_{2}\left(\left(1-x\right)\right)=-2$
$2log\left(x\right)-log\left(x+6\right)=0$
$\log_{2}\left(\left(x^2-5x-4\right)\right)=1$
$\log_{144}\left(12\right)=x$
$2\cdot log\left(x\right)-1\cdot log\left(x+6\right)=0$
$3x\cdot \log_{3}\left(4\right)=6$
Logarithmic Equations
~ 0.04 s
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