$2x^2-x\:-\:36\:=0$
$\left(6^2+1\right)\left(6^4+1\right)\left(6^8+1\right)$
$\lim n\to\infty\left(\left(1+\frac{1}{2n}\right)^{n^2}\right)$
$-\:6\:+\:7\:-\:8\:-\:5\:+\:12\:-\:17$
$\frac{729-512b^3}{9+8b}$
$\left(\frac{1}{2}\right)^{-5}$
$7^{9\:}.\:7-4$
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