$\left(\frac{9}{18}-\frac{2}{4}\right)$
$\lim_{x\to\infty}\left(\frac{\left(ln\left(x\right)\right)^3}{x}\right)$
$\frac{\left(x+1\right)}{x^2-2x-8}$
$\frac{x}{1-\frac{x^8}{6}}$
$0+\left|-4\right|$
$y^1=-\frac{y}{x-3}$
$\sqrt[3]{8a^6}b^{-3}$
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