$\left(x^{\frac{3}{2}}\right)\left(x^{-\frac{1}{2}}\right)x$

$x^{12}+10x^6y^2\:+25y^4$

$\frac{b}{6}=3$

$\frac{2x^4-3x^2+6x-2}{x-3}$

$\left(4-x\right)\left(x+3\right)+3x^2>2\left(1-x\right)^2+16-x$

$2\left(-4-8\right)+\left|5+6+2\right|-\left(7-8+1\right)-6$

$\left(-1.2\right)\cdot3$