$5X^3+2X^3-7Y^2-9Y^2$
$10ab-2bc+4cd$
$2x^2-98=0$
$21-65\cdot7-\left|5-81\cdot\left(-9\right)\right|$
$\frac{2}{5}^3x\:\frac{5}{4}^2$
$\:\:\left(3xy-4z-6\right)\left(4x-6y-8\right)$
$x\left(z+4\right)^2\left(x+1\right)$
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