$2.\:\left(2+5\right)$
$5x^3-3x^2-6x-4,8x^3-2x^2-3,7x^2-9x-1$
$-4\:+\:-8\:+\:5$
$2\left(3v+8\right)=40$
$\frac{\left(\left(3a+5\right)x^2-2bx^2+6x+3\right)}{x+1}$
$4.8\cdot2^3$
$24x^2-54x$
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