$\int\:\frac{5cosx}{5+sin^2x}dx$
$2x^2+3x=1$
$\left(4n^4.n\right)^2$
$\int x\left(4x-\frac{2}{x}\right)dx$
$\frac{9x^5-3x^3-6x+12}{3x}$
$9\sin\left(x\right)^2-cosx^2=7$
$x^2+7x+10\cdot x+3$
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