$2x^2-3x+9=0$
$\left(-5\right)\left(-4\right)\left(-2\right)\left(-1\right)$
$-3,1\cdot2$
$\frac{\left(6zw^4\right)}{\left(8z^2w^6\right)}$
$7x-4+5\left(x+3\right)$
$\left(2x^2y^3+4x^3\cdot y^5\right)^2$
$-3\left(-5x+1\right)<=4\left(2x-3\right)$
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