$\left(\frac{4}{a^2}\right)^3$
$x+4y-8z=-8\:\:\:\:$
$-3\left(5x^3-13x^2-36x+36\right)$
$8\left(-4x+3\right)$
$\left(14x^b-8y^{1-n}\right)^3$
$\int\frac{3x+2}{3x^3-2x^2-12x+8}dx$
$\int_{\left(4-3x\right)}^{\left(x^2+x-1\right)}\left(3t^2-2\right)^2\:dt$
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