$\lim_{x\to\infty}\left(\frac{4x+2}{\sqrt{x^2+4}}\right)$
$-y-8$
$\sqrt[5]{32.x^2.y^8}$
$2y^{0.6}r^{-0.3}p$
$+3\:+\:5\:-\:3\:+\:6\:-\:8\:+\:3\:+\:2\:-\:4$
$x\left(x+2x^{24}+50\right)+25$
$\frac{dy}{dx}=\frac{\left(7+x^4\right)}{\left(yx^2+y^4x^2\right)}$
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