$\int_{-\infty}^3\left(\frac{1}{x^2+9}\right)dx$
$\sec\left(x\right)=\frac{\sec^2\left(x\right)-\tan^2\left(x\right)}{\sec\left(x\right)+\tan\left(x\right)}+\tan\left(x\right)$
$s+-6=-2$
$\frac{d}{dx}\left(arc\:tan\:\left(\frac{xsen2}{1-xsen2}\right)\right)$
$x^2-26xy+169y^2$
$7\cdot7\cdot7$
$-7-8+2+2$
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