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Find the limit of $\frac{\sqrt{z+6}-4}{z-10}$ as $z$ approaches $10$

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$\lim_{z\to10}\left(\frac{\sqrt{z+6}-4}{z-10}\right)$

Main topic:

Limits

Related Formulas:

4. See formulas

Time to solve it:

~ 0.08 s (SnapXam)