$\int-10tan^2\left(x\right)sec^2\left(x\right)dx$
$xy'=y^2,\:y\left(1\right)=1$
$\sqrt[3]{125}+2^2.1$
$3.7\left(-3\right)\:$
$\frac{1}{2}log\left(x\right)+4log\left(y\right)-4log\left(x\right)$
$-25e^6+4f^4$
$x+1=1-4x$
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