$\frac{dy}{dx}+\frac{y}{10}=5$
$sin\left(t\right)dt+2xcos^3\left(t\right)dx=0$
$\int x^{\frac{3}{5}}\:dx$
$9x^2+6x^2-1$
$-10x+8+4x-8$
$\frac{dy}{dx}=x^2\sqrt[3]{y^2}$
$-1^3+2.-1^2-2$
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