$x^2-6x+5<0$
$2m^2-5m+4$
$-x^2+6x+7$
$x^2+2x-1\ge0$
$\int\frac{6x}{\left(x-2\right)\left(x+3\right)}dx$
$24\left(3y^2\right)+128$
$\lim_{x\to0}\left(\frac{\left(\sqrt[3]{x+27}-3\right)}{\left(\sqrt[4]{x+16}\right)}\right)$
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