$535+8$
$\int\frac{z}{2x^2+8}dz$
$x^4-12^2+3$
$\lim_{x\to0}\left(\frac{\tan\left(2x\right)}{x^2\sin\left(x\right)}-\frac{2}{x^2}\right)$
$2\cdot6+8$
$\int\left(\frac{1}{2-x^2}\right)dx$
$1 - ( 4 ) - ( 5 - 4 + 2 )$
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