$x'=\frac{-100t}{\left(x-10\right)}$
$\int_0^3\left(\frac{3}{y^2-9y-112}\right)dy$
$x^2-15x-16=0$
$-3-2\left(5+1\right)$
$\left(a-b\right)+\left(2a-3b-c\right)+\left(-4a+5b\right)$
$\left(secx\right)\left(tan2x\right)+secx$
$\frac{\cos\left(-x\right)}{1+\sin\left(-x\right)}=sec\left(x\right)+\tan\left(x\right)$
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