$6\sqrt[5]{x^3y^2}+5\sqrt[15]{x^9y^6}$
$\frac{x^2+5}{x^2-4}$
$\left(6x\right)^3+\left(2y\right)^3$
$\frac{19}{18}x-\frac{95}{6}=0$
$\left(-9\right)x\left(+8\right)$
$\frac{d^2}{dy^2}\left(\arccos\left(x\right)\cdot\arccos\left(y\right)=\pi\right)$
$a^4\cdot a^{-8}$
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