$x^2+x-10$
$\int\left(\frac{1x}{x^2-5x+6}\right)dx$
$\left(9a^{-6}\right)^1$
$\left(x+3\right)^2\left(x+2\right)+\left(x-3\right)\left(x-1\right)$
$\left(2a+8\right)^2$
$\left[-13+\left(24-68\right)\right]-\left(-48+95\right)$
$\left(4x^2+1\right)\left(4x^2+1\right)$
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