$\frac{1}{x-4}+\frac{1}{x+4}=\frac{16}{x^2-16}$
$5x+2\le0$
$\left(3z^3+1\right)\left(3z^3\right)$
$-2x^3-t^2+1=0$
$x^2+x-30=0$
$19+n=30$
$\left(x-200\right)\cdot\left(x+200\right)$
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