$\left(1+2\tan\:\left(x\right)\right)^2\:-\:2\tan\:^2\left(x\right)$

$\int\frac{\sqrt{x^2+2}}{x}dx$

$y'=\sec\left(x\right)+y\cdot\tan\left(x\right)$

$\left(7\right)\left(2\right)+24-\left(-6\right)$

$2-\left(10+2\right)+\left(13-12\right)-\left(5-7\right)$

$80\:+\:34$

$\int_0^4\left(8.8e^{-0.027t}\right)dx$