$\int\frac{\left(2x-3\right)}{\left(x-1\right)^3}dx$
$\int\left(\frac{4x}{x^2-1}\right)dx$
$\left(-\frac{3}{10}xy+\frac{1}{2}y^{2}\right)+\left(-\frac{1}{2}y^{2}+\frac{2}{4}x^{2}\right)$
$\left(2f-5g\right)^2$
$-8x-8y=-64$
$2x^3+6x^2-x-5$
$3-\left(-3-7+4-6\right)$
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