$\frac{15x-4}{2}<1+6x$
$v+9=-48$
$\left(z^3+8\right)\left(z^3-5\right)$
$\int_3^{\infty}\left(xe^{-5x}\right)dx$
$7\:\:x+5^2\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:2$
$\frac{x^3+3x^2-9x-18}{x^2-9}$
$y'=xy-1$
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