$y'=\frac{4y}{x\left(y-3\right)}$
$-2x-8>10$
$\int\left(x^3+\frac{1}{\sqrt{x}}\right)\cdot\ln\left(x\right)dx$
$\lim_{x\to-0}\left(4x+5\right)$
$3x+9>3$
$1-\tan^2\left(a\right)=2-\sec^2\left(a\right)$
$\sin\left(2x\right)=2\cos^2\left(x\right)$
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