$-2x-3x^2-5=-1$
$\lim_{x\to0}\left(\frac{1}{3x}-\frac{1}{\sin3x}\right)$
$xy\:dy=\left(y^2+9\right)dx$
$\left(\frac{1}{4}x-\frac{1}{3}y\right)^2$
$24x^8y^3-16x^6y^7z^3$
$y^{'\:}=e\frac{e^{-x}}{seny};\:y\left(1\right)=0$
$2x^7+3x^6-5x^5$
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