$\lim_{x\to\infty}\left(\frac{x^2-11}{x^2-9}\right)$
$\frac{1}{sec^2x}=\:cos^2x$
$\frac{9}{1-x^6}$
$x^{3}\cdot4x^{3}$
$\sqrt{1.66666}$
$5-4\cdot5$
$3\frac{d^2y}{dx^2}+3\frac{dy}{dx}+3y=0$
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