$6\tan\left(3x\right)=6$

$-\left[-a+\left\{-a+\left(a-b\right)-\left[a-b-c\right]-\left[-\left(-a\right)+b\right]\right\}\right]$

$\int\frac{3x+1}{x^2+1}dx$

$\left(6+3i\right)x^2+\left(1-2i\right)x+1-i=0$

$4+5y^3+2x^2-5$

$\frac{5}{6}\left(0.5-1\right)^{-2}-\left(0.1\right)^{-1}+0.6666-\sqrt[3]{-0.125}$

$3b-12a$