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Factor the difference of squares $x^4-81$ as the product of two conjugated binomials
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$\lim_{x\to3}\left(\frac{\left(x^{2}+9\right)\left(x^{2}-9\right)}{x-3}\right)$
Learn how to solve limits by direct substitution problems step by step online. Find the limit (x)->(3)lim((x^4-81)/(x-3)). Factor the difference of squares x^4-81 as the product of two conjugated binomials. Factor the difference of squares \left(x^{2}-9\right) as the product of two conjugated binomials. Simplify the fraction \frac{\left(x^{2}+9\right)\left(x+3\right)\left(x-3\right)}{x-3} by x-3. Evaluate the limit \lim_{x\to3}\left(\left(x^{2}+9\right)\left(x+3\right)\right) by replacing all occurrences of x by 3.