$5-0.008$
$\lim_{x\to\infty}\left(\frac{-x^3-3x^2-6x-6}{e^x}\right)$
$4x-3y+\frac{12x-6y}{2}$
$2x+y\:+12=3x+14y+8$
$\left(\left(\frac{\left(x+2\right)}{\left(x+5\right)}\right)\right)^2+4$
$0\:-\sqrt[5]{2}\:.\:\sqrt[5]{16}$
$x^2-7x-1=0$
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