$2-8\cos^2=0$
$\frac{\cos2x+\sin^2\left(x\right)}{\sin2x}=\frac{1}{2}\cot\left(x\right)$
$4\left(x^4+3x^3-2x^2-5\:\right)$
$\cot^2a=\cos^2a+\cot^2\cdot\cos^2$
$\frac{2x^2+x}{2x^2-1}$
$346\cdot53$
$+1+-3\:+\:+11$
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