$4x^2-16x+16$
$\sqrt{3x}^4$
$7\cdot5-17\cdot2$
$4-x\le3+2x$
$\lim_{x\to-5}\left(\frac{4x+20}{\left|x+5\right|}\right)$
$3x+5<x+13$
$18\:-\:16\:+\:15\:-\:6\:-\:10\:+\:13$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!