$92-\left(-16\right)$
$5\left(5\right)+2\left(6\right)$
$\lim_{x\to\infty}\frac{x^3}{e^{3x}}$
$8-6w+4-9w$
$7-x>5$
$\left(16x^3\:+\:8\right)\left(4x\:+\:2\right)$
$x^{-2}y^{-5}dx+x^{-4}y^{-5}dy=0$
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