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Factor the difference of squares $x-25$ as the product of two conjugated binomials
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$\frac{\sqrt{x}-5}{\left(\sqrt{x}+5\right)\left(\sqrt{x}-5\right)}$
Learn how to solve limits by direct substitution problems step by step online. Find the limit (x)->(25)lim((x^1/2-5)/(x-25)). Factor the difference of squares x-25 as the product of two conjugated binomials. Simplify the fraction \frac{\sqrt{x}-5}{\left(\sqrt{x}+5\right)\left(\sqrt{x}-5\right)} by \sqrt{x}-5. Evaluate the limit \lim_{x\to25}\left(\frac{1}{\sqrt{x}+5}\right) by replacing all occurrences of x by 25. Calculate the power \sqrt{25}.