$f\left(x\right)=\left(1+3^2\right)^{\frac{1}{2}}$
$\left(6x^3+2x-6\right)\left(x+2\right)$
$7.9+8.7$
$\frac{6x-8}{4}$
$\left(7\sqrt{5}\right)\left(6\sqrt{5}\right)$
$\left(a^2b^3\right)\cdot\left(-a^3b^4c\right)$
$3x^4+4x^3$
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