$5x^2-7x-6\:\:9x^2+3x-4$
$4+7+x+6x$
$\lim_{x\to4}\left(\frac{ln\left(x-3\right)}{x-3}\right)$
$\frac{2}{3}m+\frac{4}{2}m^2-\frac{8}{3}m^3$
$\left(2x-y\right)dx=\left(x-3y\right)dy$
$2\cdot5^3$
$17-3y\le-2y-3$
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