$5+3\cdot9$
$\lim_{x\to\infty}\left(\frac{4x^4+x+1}{2x^3-5}\right)$
$\frac{0}{4}$
$\int\frac{\tan^2\left(x\right)}{16\sec^3\left(x\right)}dx$
$16+6x-x^2$
$x^4+72x+36$
$\frac{d}{dx}2\sqrt{x}+\sqrt{y}=\frac{5}{3}$
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