$\left(m-2\right)\left(m-12\right)$
$\frac{d^2}{dx^2}\left(y=-40\right)$
$\left(-y-1\right)\left(y-1\right)$
$\left(y^2+x^3\right)^2$
$x'+13t^4x=8t^4x^{\frac{1}{2}}$
$\frac{dy}{dx}=\left(\frac{5}{4x}+6x^2+1\right)$
$\int\:\frac{1}{x^4-x^2}dx$
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