$-\:52\left[3\left(2x\:+\:4\:y\right)\:+\:7\left(3x\:-\:4\:y\right)\right]$
$\left(r^6\right)^7$
$16a^2-1$
$\left(2x-6\right)^4$
$2x^2-16\ge0$
$\lim_{x\to\infty}\left(\sqrt{\frac{x^2+x+3}{x^2-1}}\right)$
$32x-14=-14x+32$
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